Integrand size = 18, antiderivative size = 18 \[ \int \frac {a+b \tanh (e+f x)}{(c+d x)^2} \, dx=\text {Int}\left (\frac {a+b \tanh (e+f x)}{(c+d x)^2},x\right ) \]
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Not integrable
Time = 0.02 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {a+b \tanh (e+f x)}{(c+d x)^2} \, dx=\int \frac {a+b \tanh (e+f x)}{(c+d x)^2} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {a+b \tanh (e+f x)}{(c+d x)^2} \, dx \\ \end{align*}
Not integrable
Time = 5.64 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.11 \[ \int \frac {a+b \tanh (e+f x)}{(c+d x)^2} \, dx=\int \frac {a+b \tanh (e+f x)}{(c+d x)^2} \, dx \]
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Not integrable
Time = 0.06 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.00
\[\int \frac {a +b \tanh \left (f x +e \right )}{\left (d x +c \right )^{2}}d x\]
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Not integrable
Time = 0.25 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.72 \[ \int \frac {a+b \tanh (e+f x)}{(c+d x)^2} \, dx=\int { \frac {b \tanh \left (f x + e\right ) + a}{{\left (d x + c\right )}^{2}} \,d x } \]
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Not integrable
Time = 2.91 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.94 \[ \int \frac {a+b \tanh (e+f x)}{(c+d x)^2} \, dx=\int \frac {a + b \tanh {\left (e + f x \right )}}{\left (c + d x\right )^{2}}\, dx \]
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Not integrable
Time = 0.26 (sec) , antiderivative size = 87, normalized size of antiderivative = 4.83 \[ \int \frac {a+b \tanh (e+f x)}{(c+d x)^2} \, dx=\int { \frac {b \tanh \left (f x + e\right ) + a}{{\left (d x + c\right )}^{2}} \,d x } \]
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Not integrable
Time = 0.33 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.11 \[ \int \frac {a+b \tanh (e+f x)}{(c+d x)^2} \, dx=\int { \frac {b \tanh \left (f x + e\right ) + a}{{\left (d x + c\right )}^{2}} \,d x } \]
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Not integrable
Time = 1.87 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.11 \[ \int \frac {a+b \tanh (e+f x)}{(c+d x)^2} \, dx=\int \frac {a+b\,\mathrm {tanh}\left (e+f\,x\right )}{{\left (c+d\,x\right )}^2} \,d x \]
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